# Relationship between log x and ln derivative

### Derivatives of exponential and logarithmic functions - An approach to calculus

In this section we derive the formulas for the derivatives of the exponential function, ex e x, and the natural logarithm function, ln(x) ln (x). What is differentiation of log2 (ln(x)) at base x? . The basic difference between natural and common logarithm is the difference in their bases; it is e and From these, the properties of the logarithmic functions follow: .. that "log" is one thing and "ln" is another thing, and ask what's the difference between the two. . Logs with different bases cross the line y = 0 at x=1 with different slopes (of the tangent to the curve). . Exponential and Logarithm Derivatives.

So, on the left-hand side right over here, this is going to be the derivative of e to the y with respect to y, which is just going to be e to the y times the derivative of y with respect to x.

On the right hand side here, the derivative of x with respect to x is one. Now, to solve for the derivative, we just divide both sides by e to the y.

We get the derivative of y with respect to x is equal to one over e to the y power. Now, what is y equal to? Well, we know that y is equal to the natural log of x. So let's write that down.

### logarithms - The difference between log and ln - Mathematics Stack Exchange

This is equal to one over e to the natural log of x. What is e to the natural log of x going to be? The natural log of x is the power I need to raise e to, to get to x. So if I actually raise e to that power, to that exponent, I'm going to get x. This is going to be equal to one over x. So this thing simplifies to x.

We just figured out if y is equal to the natural log of x, the derivative of y with respect to x is one over x. Or you could say the derivative of the natural log of x with respect to x is equal to one over x. So just using the definition of a derivative if I were to say the derivative with respect to X of natural log of X that is gonna be the limit as delta X approaches zero of the natural log of X plus delta X minus the natural log of X.

All of that over delta X.

So now we can use a few logarithm properties. We know that if I have the natural log of A minus the natural log of B this is equal to the natural log of A over B.

So we can use that right over here where I have the natural log over something minus the natural log of something else. So all of this is going to be equal to the limit as delta X approaches zero of the natural log of this divided by that. So X plus delta X over X. X plus delta X over X all of that over delta X.

## Derivative of ln(x) from derivative of 𝑒ˣ and implicit differentiation

And actually, let me just write it that way. Well jee, all I did, if I have natural log of that minus natural log of that that's the same thing as natural log of this first expression divided by that second expression. It comes straight out of our logarithm properties. Well, inside of this logarithm X divided by X is one. And then delta X divided by X just write that as delta X over X. So that's another way of writing that.

And then we could put a one over delta X up front. So we could say this is the same thing as this is equal to the limit as delta X approaches zero of, I 'll do this in another color. So this, I can rewrite as one over delta X times the natural log of one plus one plus delta X over X. Let me close that parenthesis. So now we can use another exponent property. If I have, I'll write it out here.

## Proof: the derivative of ln(x) is 1/x

And so here, this would be the A in that case. So I could bring that out and make that an exponent on this. So this is all going to be equal to the limit as delta X approaches zero of the natural log of, give myself some space, one one plus delta X over X to the one over delta X power.

One over delta X power. Now this might start to look familiar to you, it might start to look close to the definition of E.

And we are, indeed, getting close to that. In order to get there fully I'm gonna do a change of variable. I'm going to say let's let let's let N equal delta X over X. Delta X over X. Well, in that case, then if you multiply both sides by X you get delta X is equal to NX. Again, just multiply both sides of this equation by X and swap to the sides there. And then if you want one over delta X one over delta X that would be equal to one over NX which we could also write as one over N times one over X.

Or actually, let me write it this way. Actually, that's the way I do want to write it. So these are all the substitutions that I want to do when I change a variable. And we also want to say, well look.

### 5. Derivative of the Logarithmic Function

As delta X is approaching zero what is N going to approach? Well, as delta X approaches zero we have N will approach zero, as well. Zero over X, well that's just gonna be zero for any X that is not equal to zero. And that's okay because zero is not even in the domain of the natural log of X.

- DERIVATIVES OF LOGARITHMIC
- 5. Derivative of the Logarithmic Function

So, this is going to be, for our domain, it works. That is, delta X approaches zero N approaches zero.